You are given an array with positive numbers and a number N. You should find the N-th power of the element in the array with the index N. If N is outside of the array, then return -1. Don't forget that the first element has the index 0.
Let's look at a few examples:
- array = [1, 2, 3, 4] and N = 2, then the result is 32 == 9;
- array = [1, 2, 3] and N = 3, but N is outside of the array, so the result is -1.
Two arguments. An array as a list of integers and a number as a integer.
The result as an integer.
0 < len(array) ≤ 10
0 ≤ N
all(0 ≤ x ≤ 100 for x in array)
def index_power(array, n): if n < len(array): return array[n] ** n else: return -1
Again, it's like the exercise on Codecademy. =)
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