# [Python] Checkio Solution 解答 – The Most Numbers

### Problem:

You are given an array of numbers (floats). You should find the difference between the maximum and minimum element. Your function should be able to handle an undefined amount of arguments. For an empty argument list, the function should return 0.

Floating-point numbers are represented in computer hardware as base 2 (binary) fractions. So we should check the result with ±0.001 precision.
Think about how to work with an arbitrary number of arguments.

Elementary

### Input:

An arbitrary number of arguments as numbers (int, float).

### Output:

The difference between maximum and minimum as a number (int, float).

### Precondition:

0 ≤ len(args) ≤ 20
all(-100 < x < 100 for x in args)
all(isinstance(x, (int, float)) for x in args)

Source: https://py.checkio.org

### My Solution:

``````def checkio(*args):
if len(args)>1:
return max(args) - min(args)
else:
return 0``````

### Comment:

The solution is unexpectedly simple and short. Before I didn't understand what array is but then I found that the array here was actually tuple.